Intrinsic Armor Resistances

Started 21 Sep 2018

by Tomahawk

in Ask the Team

I'm trying to understand how the intrinsic armor resistance numbers are calculated during a melee fight.
If I understand correctly the damage spam during a fight is: dmg(-resisted_dmg)
So doing 100 slash damage against someone with 26% slash resistance would show up as: 74(-26)

How does the armor resistance play into this? For example when attacking hib leather which, from the bowels of the internet, is 18.3% resistant to slash damage. Are the resistances added together? Or multiplied? i.e.
Base 26% resist: 74(-26)
If 18.3% is added: 55.7(-44.3)
If 18.3% is multiplied: 69.3(-30.7)

Which, if either, is it?

Thanks

Sat 22 Sep 2018 6:06 AM by Hammurabi0788

Don't forget to include the armors natural absorb percent. Leather has 10% correct?

Sat 22 Sep 2018 6:12 AM by Cadebrennus

Should be accurate for this patch level

http://daoc.warlordcentral.com/?module=general&action=resists

Mon 24 Sep 2018 7:43 AM by Tomahawk

I'm still trying to understand how/when an armor's intrinsic resists/sensitivities are calculated. And is it represented in the parenthesis in the damage chat?

Don't forget to include the armors natural absorb percent. Leather has 10% correct?

Is that absorb percent included in the parenthesis also?

Where can I see the equation? or a reasonable representation of it.

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